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Find the 7th term of a geometric sequence with t1 = 6 and r = 3
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A 652 B 1458 C 486 D 4374
the 'n' th term of a GP is given by t1*r^(n-1) where t1 is first term =6 and r=3 so put n=7 in that equation....
b?
follow what hartnn gave you \[ \large t_7=t_1\cdot3^6= \]
so whats 6*3^6 ?
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18^6?
ohh,its actually 6*(3^6)=6*729=4347
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