Mathematics
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OpenStudy (anonymous):
What is the solution set of |x – 2| + 4 = 3
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OpenStudy (anonymous):
i jus need to see how to work it out
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
|x – 2| + 4 = 3
Ix-2I=-1
NOW, x-2=-1 for x-2<0
x=1
AND x-2=1 for x-2>=0
x=3
OpenStudy (anonymous):
there is another one that i need help with too |2x + 4| < 12?
OpenStudy (anonymous):
|x – 2| + 4 = 3 actually that has no solution
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OpenStudy (anonymous):
oh thats what i got
OpenStudy (anonymous):
what about this one |2x – 3| – 10 = –1?
6 or –3
6 or 3
6 or –6
No solution
OpenStudy (anonymous):
|2x – 3| – 10 = –1
I2x-3I=9
NOw,
2x-3=-9 AND 2x-3=9
x=-3 x=6
OpenStudy (anonymous):
oh i see how you got it
ok thanks
OpenStudy (anonymous):
|2x + 4| < 12
-12<2x+4<12
-16<2x<8
-8<x<4
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OpenStudy (anonymous):
hey what would be this one |5x – 2| greater than or equal to 8
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
i would say it is greater than
OpenStudy (anonymous):
Hint: IxI=x if x>=0 AND -x if x<0
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OpenStudy (anonymous):
THAT SHOULD HELP U SOLVE THESE TYPE OF PROBLEM
OpenStudy (anonymous):
r u getting MAD
OpenStudy (anonymous):
@sauravshakya
OpenStudy (anonymous):
@85295james
OpenStudy (anonymous):
Nope
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OpenStudy (anonymous):
no not mad see :)
OpenStudy (anonymous):
oh ok i dont want you guys getting mad
OpenStudy (anonymous):
medal please :)
OpenStudy (anonymous):
i gave it to somebody allready
OpenStudy (anonymous):
:(
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OpenStudy (anonymous):
:(
OpenStudy (anonymous):
then open a new question
OpenStudy (anonymous):
ok