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Did I do this correct Solve the inequality 4x + 5 < 2x - 11 4x + 5 < 2x - 11 -2 -2 2x + 5 < -11 +5 +5 2x < 6
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2x < 6 2 2 x < 3
and do i need to flip the sign
x > 3
` 4x + 5 < 2x - 11 Subtract 2x from both sides: 2x + 5 < -11 Subtract 5 from both sides: 2x < -16 Divide both sides by 2: x < -8 ` That's how you do it.
oh i forgot to subtract the 5 :P
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thx @Hero
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