Question

determine the equation of a line that passes through(-1,2) and perpendicular to the line 2x-3y+5=0

Answer 1

answer please

Answer 2

\[y=-\frac{3}{2}x+\frac{1}{2}\]

Answer 3

From the equation find the slop by solving for y and let it to be m
the slop of the line you are looking for should equal to -1/m
then use the formula slope=(y-2)/(x+1)

Answer 4

Solve the given line equation for y. \[y=\frac{2 x}{3}+\frac{5}{3} \]
y = m x + b
Replace y, m and x with 2, -3/2 and -1 respectivley.
Solve for b, 1/2 .