Question

(EARLY ALGEBRA II) bx+a=dx+c
Solve for x. State any restrictions on the variables.

Answer 1

move dx to the right side and a to the left
bx-dx=c-a take the x out as a factor of the left side
x(b-d)=c-a divid both side by b-d
x=(c-a)/(b-d)

Answer 2

=> b must not equal d

Answer 3

If b=d you would have division by zero

Answer 4

@TheMind @ajdirig
Thank you guys so much :) Really cleared things up for my. Literal equations have never really been my forte! I appreciate it! :D