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Mathematics 21 Online
OpenStudy (anonymous):

What is the exact value of the square root of the quantity 98 over 12.? Simplify if possible.

OpenStudy (cwrw238):

= sqrt 98 / sqrt 12 = sqrt 2 * sqrt 49 ------------ sqrt4 * sqrt 3 = 7 sqrt2 ------ 2 sqrt3 multiply top and bottom by sqrt3 : 7 sqrt 6 = ------ 6

OpenStudy (gabylovesyou):

sqrt(98/12) sqrt(49/6) sqrt(49)/sqrt(6) 7/sqrt(6) 7sqrt(6)/(sqrt(6)*sqrt(6)) 7sqrt(6)/6 So the answer is 7sqrt(6)/6

OpenStudy (cwrw238):

well done - thats an easier way than mine

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