Question

factor : 27a^3−8b^3

Answer 1

using this identity\[x^3-y^3=(x-y)(x^2+xy+y^2)\]what will be ur x and y here?
compare LHS of identity with ur problem

Answer 2

this is the difference of 2 cubes

x^3 - y^3 = (x - y)(x^2 + xy + y^2)

x= 3a y = 2b

Answer 3

so it would be (3a-2b)(9a+6ab+4b) ? @campbell_st ?

Answer 4

@mukushla

Answer 5

emm..note that x^2=(3a)^2=9a^2

Answer 6

so whats the answer i am so confused... @mukushla

Answer 7

u did it right just there is a little typo

it would be (3a-2b)(9a^2+6ab+4b^2)

Answer 8

right? :)

Answer 9

right, thanks !!
im going to post another one

Answer 10

ok