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A South-African sharp nosed frog set a record for a triple jump by traveling a distance of 10.3 m. Suppose the frog starts from the origin of a coordinate system and lands at a point whose coordinate on the y-axis is equal to -6.10 m. What angle does the vector of displacement make with the negative y-axis? Calculate the x component of the frog.
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|dw:1346046249387:dw| the question is something like that?
i think you can solve for the x coordinate using pythagorean theorem
\[x = \sqrt{(10.3)^2 + (-6.10)^2}\]
then...when you have the value of x... just do \[\theta = \tan^{-1}(\frac xy)\] does that help?
@zipp you there?
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