Question

Evaluate if k= -1/2:

8- k^3
------
k-2

Answer 1

Put the value of k=-1/2 in the question & solve ;)

Answer 2

That'd get\[8 - \left({-1 \over 2} \right)^3 \over k -\left( -1 \over 2\right)\]

Answer 3

You can also use "difference of cubes".\[a^3 - b^3 \implies (a + b)(a^2 - ab + b^2) \]

Answer 4

\[\frac{8+\frac{1}{8}}{\frac{-1}{2}-2}\]

Answer 5

Sorry. I meant\[{-1 \over 2} -2\]in the denominator.

Answer 6

so is the answer 3.25?