Question

Question on Simplifying Boolean expression (Logic Gates)
Q1) ABC + AB(bar)C + ABC(bar)
---Here I'm getting the answer AB + AC -Is that Right???
Q2) AB + A(bar)C + BC

(bar) -> Line above the letter. Also called Dash sometimes.

Answer 1

Q1 is like above ?

Answer 2

last bar is only for C, or for whole ABC ?

Answer 3

Last bar is only for C. Any yes it is as U've shown.

Answer 4

okay lets see...

Answer 5

Please do. I'm seriously stumped. (For the second one- The 1st one atleast i got something)

Answer 6

first one is correct :

Answer 7

Q2 is like above ,right ?

Answer 8

Nope. Its AB + A'C + BC.
A' as In A(bar)

Answer 9

Thats wat stumped me as i couldn't really find anything to take common and continue forth. :(

Answer 10

okay just a sec.. let me get a paper !

Answer 11

answer should simplify to : A'C + AB

im trying to work backwards...

Answer 12

ah its simple friend...

Answer 13

AB + A'C + BC

AB + A'C + BC(A + A')

Answer 14

Ok.

Answer 15

AB + A'C + ABC + A'BC

Answer 16

group 1st & 3rd terms

Answer 17

2nd & last terms

Answer 18

Wait since u said U are trying to solve it backwards, does that mean u found the answer somewhere?
U get AB(1+C)+(1+B)A'C

Answer 19

since,

1+x = 1

Answer 20

it simplifies to AB + A'C

Answer 21

i simplified it using karnaugh-map quickly.... and worked backwards hehe

Answer 22

Thanku very much. FOrgot about that Identity. :) Yes I guess i understood now. :)
-Closing thread. :)

Answer 23

glad to hear :) yw !!!

Answer 24

Just an FYI, I was stumped bby thihs for quite some time now. U helped me alot. :D

Answer 25

np :D