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Solve for x: 3x- (x-9) = 2(x+5)
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It may help to think of 3x- (x-9) = 2(x+5) as 3x- 1(x-9) = 2(x+5)
yeah i did but i got 2x-9=2x+10 so i don't know what the answer is because no number can be x. would it be null?
2x-9=2x+10 2x-9-2x=2x+10-2x 0x-9= 0x+10 0-9 = 0+10 -9 = 10... which is FALSE So there are no solutions (due to the contradiction in the last equation)
okay thanks!
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