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Solve x^2 – 5x + 10 = 0 by completing the square.
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whr r u stuck?
I'm stuck on the beginning
\[\left( x-a \right)^{2} = x^{2} + a^{2} - 2ax\]
x2+a2−2ax arrange it like this
x^2 + 10 = 5x?
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x + root10 will be sqaured
ok so can it be (x - 5/2)^2 + 15/4 = 0?
no \[\left( x+\sqrt{10} \right)^{2}\]
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