I already did the steps..just need help if my answers are correct.
Solve 3x^2 – 2x – 9 = 0

3x^2 - 2x = 9

x^2 - (2/3)x = 3

(x - 1/3)^2 = 10/9

x = (1 - sqroot10)/3

x = (1 + sqroot 10)/3

Question

I already did the steps..just need help if my answers are correct.
Solve 3x^2 – 2x – 9 = 0


3x^2 - 2x = 9

x^2 - (2/3)x = 3

(x - 1/3)^2  = 10/9


x = (1 - sqroot10)/3

x = (1 + sqroot 10)/3

anonymous · Answer

The roots are
$$
\left\{\left\{x\to \frac{1}{3} \left(1-2
   \sqrt{7}\right)\right\},\left\{x\to \frac{1}{3}
   \left(1+2 \sqrt{7}\right)\right\}\right\}
$$

anonymous · Answer

so my answers are correct or wrong?

anonymous · Answer

They are not correct.

anonymous · Answer

ok