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Solve for h: A=1/2 b(h+y)
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\[ A =\frac 1 2 b(h+y) \] Is this your problem?
\[ 2 A= bh +by\\ bh = 2 A -by\\ h =\frac {2 A -by}b=\frac {2A}b -y \]
wow thank you so much!
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