Question

the perimeter of a rectangle is 54ft. Twice the length is 3ft. more than the width. What is the size of the rectangle? Legnth_____ft. Width_____ft

Answer 1

let the length be L

twice the length is 3ft more than the width so...

2L = W + 3 <=== W is width

the formula for perimeter is

L + L + W + W = P

if we substitute 2L = W + 3 here...

L + L + (2L - 3) + (2L - 3) = P

so if we substitute P = 54....

L + L + 2L - 3 + 2L - 3 = 54

combine like terms...

6L - 6 = 54

add 6 to both sides...

6L = 60

divide both sides by 6

L = 10

it says that 2L = W + 3

2(10) = W + 3

20 = W + 3

so W = 17

does that help?

Answer 2

Thank You :)