Question

if (x) = 2x^3+Ax^2+4x-5
f(2)=5 what is the value of A?

Answer 1

f(x) = 2x^3+Ax^2+4x-5
then f(2) = ?

Answer 2

5

Answer 3

if it is not given then? what would you do?

Answer 4

I dont know but it is given here . very new to concepts of function. plz help me solve this equation

Answer 5

f(x) = 2x^3+Ax^2+4x-5
f(a) = 2a^3+Aa^2+4a-5
f(b) = 2b^3+Ab^2+4b-5
f(2) = ?

Answer 6

:(

Answer 7

f(2)=5

Answer 8

f(2) = 2(2)^3+A(2)^2+4(2)-5

Answer 9

so u plug in the values of x=2

Answer 10

yes ..
and f(2) = 5
2(2)^3+A(2)^2+4(2)-5 = 5

Answer 11

ok so 16+A4-8-5?

Answer 12

correct?

Answer 13

A4-3

Answer 14

http://www.wolframalpha.com/input/?i=Solve [2%282%29^3%2BA%282%29^2%2B4%282%29-5+%3D+5%2CA]

Answer 15

4A - 3 = 5
A = (5+3)/4 = 2