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Mathematics 15 Online
OpenStudy (anonymous):

1/(x+a)=2/(x-1)-1/(x-a)

OpenStudy (lgbasallote):

nice equation....?

OpenStudy (anonymous):

haha, I have to solve for x, my bad.

OpenStudy (lgbasallote):

a is a constant?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Refer to the attachment.

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