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simplify: sin[(3pi over 2)+x)]
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Use the sum of angles identity for sine: sin(a+b) = (sin a)(cos b) + (cos a)(sin b) sin(3π/2+x) = (sin 3π/2)(cos x) + (cos 3π/2)(sin x) = (-1)(cos x) + (0)(sin x) = -cos x
what they said ^^
thank you :)
@camjan Welcome:)
hehe.. can i add u on facebook?
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@camjan yeah, sure:)
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