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log(w-3)+log(w)=log(28) log is in base 10
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solve for w
log a +log b= log (ab)
log (w-3)+log w= log ((w-3)w)=log28 therefore w(w-3)=28...can you solve this?
quadratic formula?
w^2-3w-28=0
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yes solve it
so its 7 and not -4 right?
w^2-7w+4w-28=0
what? where do you get 7w and 4w?
yes it's 7...coz for negative number log is not defined
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@Ldaniel clear?
no
why ?
oh wait cause 7-4 =3
yes i split -7w+4w=-3w
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