Question

solve (x+4)^2=5

Answer 1

x=sqrt(5)-4

Answer 2

(use reverse pemdas) (sadmep)

Answer 3

\[x^2+8x+16=5 --> x^2+8x+11=0 \]

Answer 4

It dos not have real solutions

Answer 5

u need to use the quadratic formula

Answer 6

ok a momento please

Answer 7

there are 2 solutions \[-4+3\sqrt(3) \] and \[-4-3\sqrt(3) \]

Answer 8

u have
\[ \large (x+4)^2=5 \]
then
\[ \large x+4=\pm\sqrt{5} \]
then
\[ \large x=-4\pm\sqrt{5} \]