Question

Find an equation for the quadratic function described: The function f has zeros 5 and 1 and f(0)=1. THANKS SO MUCH

Answer 1

function with zeros at 5 and 1 is

f(x) = a ( x - 5 ) ( x - 1 )

= f(x) = ax^2 - 6ax + 5a

= f (0) = 5a = 1

= a = 1/5

Hence , f(x) = 1/5 x^2 - 6/5 x + 1

Answer 2

Thank you!