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7t^3=2t(t+5/2)
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distribute 2t first \[\implies 7t^3 = 2t(t) + 2t(\frac 52)\] simplify... \[\implies 7t^3 = 2t^2 + 5t\] put everything on one side \[\implies 7t^3 - 2t^2 - 5t = 0\] can you solve for t now?
i thnk so
wonderful
im at t(7t^2-2t-5)
good. now equate the factors to 0
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@kingkri One answer is t=0, and 7t^2-2t-5 =0 You could find the other two values of t by factoring trinomials. Or applying the Quadratic Formula: \[t=−b± \frac{ \sqrt{b ^{2}−4ac} }{ 2a }\] Can u find a=?, b=? and c=?
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