Question

A bus moves away from rest at a bus stop with an acceleration of 1ms^-2. As the bus stars to move a man who is 4m behind the stop runs with a constant speed after the bus. If he just manages to catch the bus find his speed?

Answer 1

@Callisto @davian @inkyvoyd

Answer 2

I don't know if it works.


Let s be the distance travelled by bus, distance travelled by the man = s+4
Time for the bus and man travelled is the same

For the bus: s = ut + (1/2) at^2, where u = 0ms^-1, a = 1ms^-2
For the man, s + 4 = vt

No... it doesn't work. I need one more equation :(