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a football is kicked vertically upward from a height of 2 feet with an initial speed of 70 feet per seconds. formula h=2+70t-16t(squared) describe the balls height above ground (h) in feet(t)seconds ater kicked use the formula to find the balls height 3 seconds after it was kicked the balls height 3 seconds after kicked was ? feet
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All you need to do is plug in 3 for t:\[h=2+70(3)-16(3^2)\]
so the answer is 72
uh I get 68 (in my head)
lol i am notr that good this my 5th time to take this class. 68 was right thank you
I got 68 also :)
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