Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?
let the age of Tony's age be x since combined age is 56 Belinda's age = 56-x Belinda is 8 more than twice Tony’s age. so 2*x+8=56-x can u solve this to get x ??
tony's age=x blinda]s age=y x+y=56 y=2x+8 so combine the two previous equation and find the ages
how would i combine them?
like i did and u will get 2*x+8=56-x can u solve this to get x ??
is it 2 times x? is that why you put the *
yes
yes,two times x *=multiplication
let me give u hint to solve 2x+8=56-x 1. Add x to both sides 2. Subtract 8 from both sides what u get?
would i subtract 8 from 8 and 56?
yes,both
so did u get something like this? 3x=48 ?
x = 16
?
thats correct :) good work. so tony age = 16 Belinda age= 56-16 = ??
40
awesome :) u got both's age .
how would i write the answer and thank you
The age of Tony is 16 years, and the age of Belinda is 40 years.
Join our real-time social learning platform and learn together with your friends!