Based on Newton's 3rd law!
If there are two object's with different forces one at 20N and the other 60N collided head on! What would be the result?
Im confused with Netwon's 3rd law!
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OpenStudy (anonymous):
@experimentX @Callisto help!
OpenStudy (anonymous):
"For every action force there is an equal and opposite reaction force."
OpenStudy (experimentx):
bang!!
what do you think would happen?
OpenStudy (anonymous):
I think that "BANG" is not an equal reaction now is it?
OpenStudy (experimentx):
20 N ---> <---- 60 N
40 N <----
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OpenStudy (anonymous):
Really now! :)
OpenStudy (anonymous):
Interesting! :)
OpenStudy (experimentx):
both object will experience force of 40N along <---
OpenStudy (anonymous):
5000N< ---10,000N = ?!?!
OpenStudy (experimentx):
huh??
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OpenStudy (experimentx):
try to visualize forces as vectors and calculate resultant.
OpenStudy (anonymous):
Perfect. So any object with stronger force acted on a object with a weaker force the weaker object would increase based on the stronger one?
Example: 20N(Weak) ---> < --- 60N(Stronger)
= 40N <---
OpenStudy (anonymous):
I am but keep getting confused! But hopefully will understand it.
OpenStudy (experimentx):
when you push someone stronger pushing you back then what will happen?
OpenStudy (anonymous):
I'll experience a strong force?
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OpenStudy (experimentx):
you will be pushed back ... same thing happens happens
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