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A die is rolled 6 times find the probability of exactly 4 occurrences of 2 A.0.39% B.2.6% C.0.47% D.0.8%
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so it would be D? if i rounded it ?!
No absolutely not, I read this entirely wrong. I apologize lemme rework it.
the probability decreases with the more rolls... so the problem is P(2) x P(2) x P(2) x P(2) x P(not2) x P(not 2)
6!/(4!2!) * (1/6)^4 * (5/6)^2 15 * 1/1296 * 25/36 0.00803 = 0.8%
or simply, not stealing credit from @nphuong but you can write it as 6C2 and the rest.
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