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OpenStudy (wwe123):
cot² θ-(1+√3)cotθ+√3 0≤x≤π
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OpenStudy (anonymous):
What do we have to do?
OpenStudy (anonymous):
cot² θ-(1+√3)cotθ+√3 =0 ??
OpenStudy (wwe123):
cot² θ-(1+√3)cotθ+√3 =0
OpenStudy (wwe123):
0≤x≤π
OpenStudy (anonymous):
lol.....u see it is a quadratic equation in cot theta....Find the Two..values fot it ..using quadratic formula
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OpenStudy (anonymous):
|dw:1346240232867:dw|
OpenStudy (anonymous):
Try....My frnd......come on
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