Question

use natural logarithms to solve the equation
6e^2x-9=23

Answer 1

The answer to your problem expression as written is: \[x=\frac{16}{3 e^2} \]Perhaps there should have been a set of parentheses flanking the 2x.\[6 e{}^{\wedge}(2 x) - 9 = 23 \to 6 e^{2 x}-9=23\]

Answer 2

\[6 e^{2 x}-9=23\]Move -9 to the RHS, divide each side by 6 and then take the Log of each side. Can you finish the problem from that point?

Answer 3

yeah thanks

Answer 4

Thank you for the medal.