Max observes the zoo and the library from a helicopter flying at a height of feet above the ground, as shown below. What is the distance between the zoo and the library? 300 feet 600 feet 900 feet 100 feet
@jim_thompson5910
tan 30 = 300sqrt3 / GL tan 60 = 300sqrt3 / GZ find GL and GZ distance required = GL - GZ
Let H = point at the helicopter, Z = point at the zoo and L = point at the library First find GL. Then find GZ. With these two, you can find ZL Hints: tan(30) = GH/GL tan(30) = 300*sqrt(3)/GL GL = 300*sqrt(3)/tan(30) ----------------- tan(60) = GH/GZ tan(60) = 300*sqrt(3)/GZ GZ = 300*sqrt(3)/tan(60) ------------------ ZL = GL - GZ
ok so then what
type 300*sqrt(3)/tan(30) - 300*sqrt(3)/tan(60) into your calculator to get https://www.google.com/search?hl=en&newwindow=1&safe=active&rlz=1B3GGLL_enUS420US420&q=300*sqrt%283%29%2Ftan%2830+degrees%29+-+300*sqrt%283%29%2Ftan%2860+degrees%29&oq=300*sqrt%283%29%2Ftan%2830+degrees%29+-+300*sqrt%283%29%2Ftan%2860+degrees%29&gs_l=serp.12..19.46016.51592.0.53562.16.16.0.0.0.0.671.2226.3j12j5-1.16.0.les%3B..0.0...1c.fy0Y6P8xuts
thank you
np
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