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H E L P ! The area of a rectangle is x2 - 2x - 15 and the length of the rectangle is x + 3. Find the width of the rectangle.
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answers A. x – 5 B. x2 + 15 C. x + 5 D. (x – 2)(x + 3)
Area = Length * Width \[x^2-2x-15 = (x+3) * Width=(x+3)(x\pm ?)\]
do you know the answer or how to help more ?
????
factor the left hand side of the equation
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i dont know how to ..
have you done it ever before? factoring trinomials?
or you can do long division
not really , no !
i guessed i was D but it was wrong
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\[x^2−2x−15=(x+3)∗Width=(x+3)(x+A)\]\[x^2−2x−15=(x*x)+ (x*A)+(3*x)+ (3*A)=x^2+Ax +3x+3A\]\[x^2−2x−15=x^2+Ax+3x+3A=x^2+(3+A)x+3A\]\[x^2−2x−15=x^2+(3+A)x+3A\]Solution where -2 = (3+A) and -15 = 3A
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