Question

What is i^-9 ( That's i raised to the negative ninth) Not the variable i, i as in an imaginary number.

Answer 1

\[i^{-2}=\frac{ 1 }{ -1 }\]
\[i^{-1}=\frac{1}{\sqrt{-1}}\]
\[i^{-3}=\frac{1}{(-1)^{3/2}}\]

Answer 2

combine these identities until you reach i^(-9)