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–2(x – 3) ≥ 5 – (x + 3)
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distribute first \[\implies -2x + 6 \ge 5 - x - 3\] do you know how to solve for x now?
noo
do you know how to solve for x in \[-2x + 6 = 5 - x - 3\]??
-3x + 6=5-3 -3x+ 9=5 -3x=-4?
hello??
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you add x
-2x + x = -x not -3x
so that should be -x = -4 got it?
4?
2(x + 5) > 8x – 8 help with this bro
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