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so how do i find sec(90-theta) if i know sinTHETHA is 1/3 and cosTHETA is 2root2/3 and cscTHETA is 3 and secTHETA is 3root2/4?? PLEase helpp I don't know which parts to use and how? so confused..
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Try drawing the reference triangle first
that still doesnt help?
Could you show me the reference triangle?
just joined it might take a sec to draw it on this
|dw:1346289270945:dw|
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OK, could you add in the values you already know from the problem?
|dw:1346289343727:dw|
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