solve: 4(a+2)-2a=10+3(a-3)
Can you distribute 4 to the brackets on left hand side??
4a+8-2a
Yep good.. Now : 4a - 2a = ??
2a
Yep so what are you left with on left hand side now ??
..ummm do i start in the ()?
a-3 = -3a?
No you are simply left with 2a + 8 now on left hand side.. Now solve for Right hand side: Distribute 3 to the brackets..
Multiply a with 3 and then multiply a with -3 and tell me what did you get ??
. 10+3a-9?
Yep : 10 - 9 = ??
...1+3a
Yep: So finally you have got : 2a + 8 = 1 + 3a Now subtract 2a from both the sides..
..8=1+1a do i sub. 8 by 1 ...1 by 8? which ever?
a=7
Yes good.. You are right... Well Done..
thanks you
Welcome dear..
Can you do one thing here that will help you to verify your answer if it is correct or not ??
4(a+2)-2a=10+3(a-3) 4a+4*2-2a=10+3(a-3) 4a+8-2a=10+3(a-3) 4a-2a+8=10+3(a-3) 2a+8=10+3(a-3) 2a+8=10+3a-3*3 2a+8=10+3a-9 2a+8=3a+10-9 2a+8=3a+1 2a=3a+1-8 2a=3a-7 2a-3a=-7 -a=-7 a=7 check the answer: 4(a+2)-2a=10+3(a-3) 4(7+2)-2*7=10+3(7-3) 4(9)-14=10+3(4) 36-14=10+12 22=22 (CORRECT)
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