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To work this out, substitute x=1 into P(x) to get P(1) and see if it equals 0. If it does, then 1 is a root of P(x). P.S: I'm assuming you meant "Is x=1 a root of P(x)" and not "r=1".
okay i tried it and it didn't equal to 0?
So, it not a root then
p(1) = 1^3+3* (1^2)-2*2+1=3
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