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Someone please halp! what are the x-intercepts of the graph of y+12=x^2+x
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first of all you want to isolate y. y = x^2 + x - 12 Now you can use the quadratic formula to solve it. x^2 + x - 12 = 0 Do you know the formula?
no.
Maybe there is a better solution for this particular case but the general solution is \[x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\] Do you recognize this?
oh ok yes i do
Good, try to plug it in and see what you get for x :)
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ok thanks so much!
you can also, factor it as well
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