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simplify. (7r^2-6t^2+2rt) + (-5rt+4t^2-2r^2)
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\[(7r^2-6t^2+2rt) + (-5rt+4t^2-2r^2)\] \[7r^2-6t^2+2rt -5rt+4t^2-2r^2\] \[7r^2-2r^2+2rt -5rt+4t^2-6t^2\] \[(7-2)r^2+(2-5)rt+(4-6)t^2\] \[(5)r^2+(-3)rt+(-2)t^2\] \[5r^2-3rt-2t^2=(5r+At)(r+Bt)=5r^2+(A+5B)rt+(AB)t^2\]Can you solve for (A+5B)=-3 and AB = -2?
No I'm not really sure how to do that ?
If A*B = -2 then A or B is either plus or minus 1 or plus or minus 2
One will be positive, the other negative.
ok i got you so far
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So which combination solves (A+5B)=-3?
the -2?
What is -2?
you said a * b = -2
Yes. What are A and B?
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are they -2?
-2*-2 = 4
im not sure i don't like math
u still there?
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