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Simplify: ( x^2-16) /(2x^2-7x-15) divided by (x+4) /(4x^2-22x+10)
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try first factorizing each of the polynomials then change the division into a multiplication by flipping the second fraction cancel common terms
Can you show me
x^2-16=x^2-4^2=(x-4)(x+4) (difference of 2 squares) 2x^2-7x-15=2x^2-10x+3x-15=2x(x-5)+3(x-5)=(2x+3)(x-5) (grouping method) 4x^2-22x+10=4x^2-20x-2x+10=4x(x-5)-2(x-5)=(4x-2)x-5) now just rearrange and cancel common terms
Can show me in fraction form
good |dw:1346366429648:dw|
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