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Can you show me the steps. (0.1x+0.4y)(0.1x+0.4y)
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\[(0.1x+0.4y)(0.1x+0.4y) \] you need four multiplications \[(0.1x)(0.1x)+(0.1x)(0.4y)+(0.1x)(0.4y)+(0.4y)(0.4y)\]
first product gives \(0.01x^2\) second two both give \(0.04xy\) and last one gives \(0.16y^2\)
0.01x^2+0.08xy+0.16y^2
combining like terms you get \[0.01x^2+0.08xy+0.16y^2\]
Thank youu!
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