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OpenStudy (anonymous):
x^2+4x-12=0 solve using completing the square
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OpenStudy (zzr0ck3r):
x^2+4x-12=0 (x+2)^2 = 12 + 4 x+2 = +-sqrt(16) x = +-4-2 so x = -6 or x = -2
OpenStudy (anonymous):
-6 and -2
OpenStudy (anonymous):
-6 and 2
OpenStudy (anonymous):
x=4-2= 2 @zzr0ck3r
OpenStudy (zzr0ck3r):
yes 2 not -2 sorry
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