Question

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Answer 1

hmm well with which problem do u want me to show u the processs

Answer 2

hmmm should we be using the quadratic formula or r we factoring?

Answer 3

No I will I just need to know which method I should be using the quadratic formula or are we factoring? I have a hunch we have to factor

Answer 4

ok So ill do the factoring method and If i get stuck we will use the quadratic formula

Answer 5

\( -21x^2-17x+8=0 \)
Keep in mind that our equation is in the form \(ax^2+bx+c\)
In this particular case our a=-21 b=-17 c=8
Since we cant factor anything our first step will be to multiply a*c
So we will multiply -21*8=-168
Now we need to find 2 numbers that when u multiply them it gives you our a*c which is -168 and when you add them will give you our b, which is-17
so the 2 numbers that I have found are -24 and 7
-24*7=-168
-24+7=-17
So now we will replace our -17x with -24x+7x
\(-21x^2+7x-24x+8=0\) The next step would be to bracket the first 2 and last terms
\((-21x^2+7x)+(-24x+8)=0\) We then factor each bracket separately
\(-7x(3x-1)-8(3x-1) =0\)
\((-7x-8)(3x-1) =0\)
Now we know that since the equation equals zero then either of the brackets must equal 0
-7x-8=0
-7x=8
x=-8/7
and
3x-1=0
3x=1
x=1/3
Therefore our x=-8/7 and 1/3

Answer 6

@shjej5835 did u follow?

Answer 7

Can u do the next one on ur own?

Answer 8

i just guessed. I just totally play around
I got 25 and 12

Answer 9

\( 20x^2+25x+12x+15=0 \)
\((20x^2+25x)+(12x+15)=0 \)
\(5x(4x+5)+3(4x+5)=0 \)
\((5x+3)(4x+5)=0\)
soooo (5x+3)=0 and (4x+5)=0
now solve for x

Answer 10

5x+3=0
5x=-3
x=-3/5
and
4x+5=0
4x=-5
x=-5/4
so x=-3/5 and -5/4

Answer 11

lol

Answer 12

like if u dont understand what i did then u need to begin with easier and simpler examples and thennnnnn it will become second nature

Answer 13

lol i am gonna tear soon tooooo. It is sooo late and I am tired. Gnite

Answer 14

yw :)