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solve 3x^3-4x=1 please explain step by step please ;__;
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first subtract 1 from both sides \[\large \implies 3x^3 - 4x - 1 = 0\] now you find factors for this are you familiar with the factor theorem?
i can't factor with ^3 :(
do u know a technique where u can find whether (x+1) and/or (x-1) is a factor of given polynomial ?
nope
add coefficient of odd terms add coefficient of even terms what u get?
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if u get those equal,then x+1 is factor if coefficient of odd terms+coefficient of even terms=0, then x-1 is factor
so would it be (x+1) .?
yup,now can u divide your polynomial with x+1 to get a quadratic equation,that u can solve.
OH OK I GOT IT
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