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divide as indicated x+3/3 divided by 3x+9/2
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\[\huge \frac{\frac{x+3}3}{\frac{3x+9}2} \implies \frac{\frac{x+3}3}{\frac{3(x+3)}2}\] does that help?
no
next step : \[\frac{ x+3 }{ 3} \times \frac{ 2 }{ 3(x+3) }\left[\begin{matrix}? & ? \\ ? & ?\end{matrix}\right]\]
i really have no idea i got 7 when i divided x+3/3
|dw:1346381837409:dw|
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