Question

find equations of the lines passing through (1,3) and have the following characteristics
a) slope of -2/3
b) perpendicular to the line x+y=0
c) passing through the point (2,4)
d) parallel to the x-axis

Answer 1

what ones you need help with?

Answer 2

all of them :/

Answer 3

a) we know the equation for a line is y = mx+b where m is slope and b is y intercept. So
3 = (-2/3)*1 + b
b = 3+2/3
b = 11/3 so a is
y = (-2/3)x+11/3

Answer 4

b)x+y = 0 so y = -x we know this slope is -1 and perpendicular means the negative recipicle of the slope so our new slope is 1
so 3 = 1 + b s0 b = 2
so our answer is y = x+2

Answer 5

c) we now have two points (1,3) and (2,4) so our slope is (4-3)/(2-3) = -1
so choose a point to figure out b
3 = -1*1 + b
b = 4
so y = -x+4

Answer 6

d)the x axis is a slope of 0 so
y = 0*x+b we use the point
3 = 1*0 + b
b = 3
so y = 3 is the answer

Answer 7

awesome, thanks!

Answer 8

nonono you need to understand it, tell me what part you dont get?