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Is it possible ? \[(2n+2)2^{n}n! = 4n^{n} + 4^{n} (n!)\]
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i think its wrong but is there a smilar solution for \[(2n+2)2^{n}n! = ?\]
I think \[2(2^n) = 2^{n+1}\]
for sure
\(n^n\) grows very fast. i think this is unlikely
in any case it is not true if \(n=5\) just checked
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hmm yes i tried some numbers too and it was not true..
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