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Mathematics 19 Online
OpenStudy (anonymous):

Can someone please help me with this!!!! I do not understand... PLEASE!!...

OpenStudy (anonymous):

OpenStudy (anonymous):

1 AND 2 are correct

OpenStudy (anonymous):

I dont think 3 is correct

OpenStudy (anonymous):

1 is right 2 is right 3 is wrong

OpenStudy (anonymous):

for 3, add 4 all the way across, then divide by 2

OpenStudy (anonymous):

I dont understand.. where do i add 4 at and why?

hartnn (hartnn):

-8≤2x-4<2 adding 4 to this means -8+4<=2x<2+4 that is adding 4 to all the terms........ get this?

OpenStudy (anonymous):

yes

hartnn (hartnn):

so what u get finally?

OpenStudy (anonymous):

so would it be the second answer -2<=x<-1??..

hartnn (hartnn):

4+2=6 when u divide by 2,u get 3 on right side.......

OpenStudy (anonymous):

oops, i put the wrong one.. i was looking at one and and thinking another..

hartnn (hartnn):

u want 4 or u got that?

OpenStudy (anonymous):

I dont have 4, 5, 7, or 8:\ and im not sure about 6 or 9... if you dont mind helping me?

OpenStudy (anonymous):

I marked what i think the answers are for 6 and 9 but i second guessed myself

hartnn (hartnn):

if u can do 4,u can do 5,6 also so.i'll tell u what to do in 5,u do 4,6 first remember this:if \[|ax+b|<c \] then \[(ax+b)<c\] or \[(ax+b)>-c\] ok ? remembered this?

OpenStudy (anonymous):

I do remember that...

hartnn (hartnn):

so continuing with 5 |2x+7|≤27 (2x+7)≤27 or (2x+7)≥ -27 so x≤10 or x≥-17 got this?

OpenStudy (anonymous):

yes..

hartnn (hartnn):

so its option A. right? can u do 4,6??

OpenStudy (anonymous):

yes. so i didnt do 6 right?

OpenStudy (anonymous):

so 4 would be a aslo if i did it right

hartnn (hartnn):

yup :)

OpenStudy (anonymous):

and 6 would be b?? i think

OpenStudy (anonymous):

or c

hartnn (hartnn):

6 was correct,C

OpenStudy (anonymous):

now i just need help with 7 i think i did 8 and 9 right

hartnn (hartnn):

what u got 8th answer? 9th is incorrect.........

OpenStudy (anonymous):

8 would just be putting the numbers in place of the letter right?

hartnn (hartnn):

but whats your final answer for 8th? use |-a|=a

OpenStudy (anonymous):

bc it doesnt say solve or anything

hartnn (hartnn):

but i think u need to get the value whats |-2|+(-2)^3 ??

OpenStudy (anonymous):

-6

hartnn (hartnn):

right,check 9th again

OpenStudy (anonymous):

im not sure about that one... or number 7

hartnn (hartnn):

whats -6d-3d ?

hartnn (hartnn):

it would be -9d so your 9th answer is 13c-9d

OpenStudy (anonymous):

o what about 7 thats the one i really dont understand

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