Question

(4(y+2)^(1/2)-2y(y+2)^(-1/2))/(y+2)

simplify

Answer 1

\[ \large \frac{4\sqrt{y+2}-2y(y+2)^{-1/2}}{y+2} \]
??

Answer 2

\[\frac{ 4(y+2)^{\frac{ 1 }{ 2 }}-2y(y+2)^{\frac{ -1 }{ 2 }} }{ y+2 }\]

Answer 3

yeah i guess you can say that

Answer 4

u must know this
\[ \large a^{-n} =\frac{1}{a^n}\]
then
\[ \large ...=\frac{4\sqrt{y+2}-\frac{2y}{\sqrt{y+2}}}{y+2} \]

Answer 5

\[ \large =\frac{\frac{4(y+2)-2y}{\sqrt{y+2}}}{y+2}=
\frac{\frac{2y+8}{\sqrt{y+2}}}{y+2}=
\frac{2y+8}{(y+2)\sqrt{y+2}} \]

Answer 6

\[ \large =\frac{2y+8}{(y+2)^{3/2}} \]