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Physics 21 Online
OpenStudy (anonymous):

A thin glass rod is bent into a semicircle of radius r. A charge +q is uniformly distributed along the upper half, and a charge of -q is distributed along the lower half, as shown in Fig. 23-34b. Find the magnitude and direction of the electric field E at P, the center of the semicircle. (a) The magnitude of the electric field at P is: q / (2*0*r2) q*r2 / (2*0) q*r2 / (*0) -q*r2 / (2*0) q / (2**0*r2)

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