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Mathematics 16 Online
OpenStudy (anonymous):

Find the vertex of the parabola by completing the square.

OpenStudy (anonymous):

x^2-6x+8=y

OpenStudy (anonymous):

A. (–3,– 6) B. (3,–1) C. (–3,1) D. (–1, 3)

OpenStudy (anonymous):

@lgbasallote

OpenStudy (anonymous):

(D)????

OpenStudy (helder_edwin):

complete the square \[ \large x^2-6x+8=y \] \[ \large y-8=x^2-6x \] \[ \large y-8+\left(\frac{6}{2}\right)^2=x^2-6x+\left(\frac{6}{2}\right)^2 \] \[ \large y-8+9=x^2-6x+9=(x-3)^2 \] \[ \large y+1=(x-3)^2 \]

OpenStudy (anonymous):

but it is (D)

OpenStudy (helder_edwin):

the vertex is (h,k) when \[ \large y-k=4a(x-h)^2 \] so the vertex of the parabola is (3,-1)

OpenStudy (anonymous):

so (B)

OpenStudy (helder_edwin):

yes

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