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Find the vertex of the parabola by completing the square.
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x^2-6x+8=y
A. (–3,– 6) B. (3,–1) C. (–3,1) D. (–1, 3)
@lgbasallote
(D)????
complete the square \[ \large x^2-6x+8=y \] \[ \large y-8=x^2-6x \] \[ \large y-8+\left(\frac{6}{2}\right)^2=x^2-6x+\left(\frac{6}{2}\right)^2 \] \[ \large y-8+9=x^2-6x+9=(x-3)^2 \] \[ \large y+1=(x-3)^2 \]
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but it is (D)
the vertex is (h,k) when \[ \large y-k=4a(x-h)^2 \] so the vertex of the parabola is (3,-1)
so (B)
yes
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